There are 10 points in a plane of which no three points are collinear and four points are concyclic. The number of different circles that can be drawn through at least three points of these points is
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a
116
b
120
c
117
d
none of these
answer is C.
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Detailed Solution
Number of points required for the fixed circle is 3. So, first select any three points from the 10 points in 10C3 ways.In these ways, circle with four concyclic points is selected in 4C3 ways. But it should be taken once then total number of circles is 10C3−4C3+1.
There are 10 points in a plane of which no three points are collinear and four points are concyclic. The number of different circles that can be drawn through at least three points of these points is