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There are three coplanar parallel lines. If any p points are taken on each of the lines, the maximum umber of triangles with vertices at these points is
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a
3pC3
b
p2(p−1)
c
p2(4p−1)
d
p2(4p−3)
answer is D.
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Detailed Solution
pC1×pC1×pC1+pC2×2pC1×3C1=p2(4p−3)
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