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There are three pigeon holes marked $M, P, C .$ The number of ways in which we can put 12 letters so that 6 of them are in $M,$ 4 are in $P$ and 2 are in $C$ is

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Correct option is B

Number of ways is 12C6 for M,6C4 for P and 2C2 for C.Thus, the required number of ways= 12C6 6C4 2C2

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There are three pigeon holes marked M, P, C. The number of ways in which we can put 12 letters so that 6 of them are in M, 4 are in P and 2 are in C is

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There are three pigeon holes marked $M, P, C .$ The number of ways in which we can put 12 letters so that 6 of them are in $M,$ 4 are in $P$ and 2 are in $C$ is