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Q.

There are three pigeon holes marked M, P, C. The number of ways in which we can put 12 letters so that 6 of them are in M, 4 are in P and 2 are in C is

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a

2520

b

13860

c

12530

d

25220

answer is B.

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Detailed Solution

Number of ways is  12C6 for M,6C4 for P and  2C2 for C.Thus, the required number of ways= 12C6 6C4 2C2
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There are three pigeon holes marked M, P, C. The number of ways in which we can put 12 letters so that 6 of them are in M, 4 are in P and 2 are in C is