Questions
There are three piles of identical yellow, black and green balls and each pile contains at least balls.
The number of ways of selecting balls if the number of black balls to be selected is twice the number of yellow
balls, is
detailed solution
Correct option is B
Let the number of yellow balls be x, that ofblack be 2x and that of green be y. Thenx+2x+y=20 or 3x+y=20 ⇒ y=20−3x As 0≤y≤20, we get 0≤20−3x≤20⇒ 0≤3x≤20 or 0≤x≤6∴ The number of ways of selecting the balls is 7.Similar Questions
The number of positive integral solutions satisfying the equation is
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