There are two circles whose equations are x2+y2=9 and x2+y2-8x-6y+n2=0,n∈I. If the two circles having exactly two common tangents, then the number of the possible values of ‘n’ is
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a
2
b
7
c
8
d
9
answer is D.
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Detailed Solution
C1(0,0) C2(4,3)r1=3 r2=25-n2-50For exactly two common tangentsr1+r2>c1c2 ⇒3+25-n2>5⇒n2<21⇒-21