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There are two circles whose equations are x2+y2=9 and $x^{2} + y^{2} - 8 x - 6 y + n^{2} = 0, n \in I$ . If the two circles having exactly two common tangents, then the number of the possible values of ‘n’ is

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Correct option is D

C1(0,0) C2(4,3)r1=3 r2=25-n2-50For exactly two common tangentsr1+r2>c1c2 ⇒3+25-n2>5⇒n2<21⇒-21

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There are two circles whose equations are x2+y2=9 and x2+y2-8x-6y+n2=0,n∈I. If the two circles having exactly two common tangents, then the number of the possible values of ‘n’ is

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There are two circles whose equations are x2+y2=9 and $x^{2} + y^{2} - 8 x - 6 y + n^{2} = 0, n \in I$ . If the two circles having exactly two common tangents, then the number of the possible values of ‘n’ is