Three boys of class X, four boys of class XI, and five boys of class XII sit in a row. The total number of ways in which these boys can sit so that all the boys of same class sit together is equal to

Question

Infinity Learn · Accepted Answer

We can think of three packets. one consisting of three boys of class X, other consisting of $$4$$ boys of class XI and last one consisting of $$5$$ boys of class XII. These packets can be arranged in it ways and contents of these packets can be number arranged in $$31$$ $$4$$! and $$5$$ ! ways, respectively. Hence, the total number of ways is $$3$$ !x $$3$$ ! x $$4$$! x $$5$$ !

Three boys of class X, four boys of class XI, and five boys of class XII sit in a row. The total number of ways in which these boys can sit so that all the boys of same class sit together is equal to

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