First slide

Permutations

Question

Three boys and three girls are to be seated around a circular table. Among them the boy X does not want any girl as a neighbour and girl $Y$ does not want any boy as a neighbour. The number of possible arrangement is:

Moderate

A

9
B

4
C

8
D

6

Solution

Clearly X should sit between the two remaining boys and Y should sit between the remaining two girls We have to arrange two groups $B_{1} X B_{2}$ and $G_{1} Y G_{2}$ along a circle. This can be done is $(2 - 1)!$ ways. But group of boys (girls) can be arranged in $2!$ ways. Thus, the required number of ways is (2) (2) (1) = 4 ways.

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App