First slide

Theorems of probability

Question

Three dice are rolled simultaneously. The probability that the sum of the numbers on them is 16 is

Easy

A

$\frac{1}{36}$
B

$\frac{1}{108}$
C

$\frac{26}{51}$
D

$\frac{13}{34}$

Solution

$n (S) = 6^{3}$
$S u m 16 = {(5, 5, 6), (5, 6, 5), (6, 5, 5), (6, 6, 4), (6, 4, 6), (4, 6, 6)}$

$n (E) = 6$

$P (E) = \frac{6}{6^{3}} = \frac{1}{36}$

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