First slide

Theorems of probability

Question

Three dice rolled simultaneously. The probability that the sum of the numbers on them is 6 is

Easy

A

$\frac{1}{36}$
B

$\frac{5}{108}$
C

$\frac{26}{51}$
D

$\frac{13}{34}$

Solution

$n (S) = 6 \times 6 \times 6 = 216$
$n (E) = \frac{(6 - 1) (6 - 2)}{2} = 10$ $(∵ n (E) = \frac{(r - 1) (r - 2)}{2})$

$P (E) = \frac{10}{216} = \frac{5}{108}$

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