Q.
Three digit numbers xyz are formed with digits 0, 1, 2, ….., 9 such that x≤y≤z then number of such numbers is
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a
150
b
504
c
165
d
425
answer is C.
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Detailed Solution
x < y < z ⇒ number of numbers = C9,3 x = y < z ⇒number of numbers = C9,2x < y = z ⇒number of numbers = C9,2x = y = z ⇒number of numbers = C9,1 Total numbers = 9C3+ 9C2+ 9C2+9=165
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