Three distinct points P3u2,2u3,Q3v2,2v3 and R3w2,2w3 are collinear then -
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a
u v+v w+w u=0
b
u v+v w+w u=3
c
u v+v w+w u=2
d
u v+w w+w u=1
answer is A.
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Detailed Solution
3u22u313v22v313w22w31=0R1→R1-R2 and R2→R2-R3⇒u+vu2+v2+vu0v+wv2+w2+vw0w2w31=0Exapand the determinantu+vv2+w2+vw-v+wu2+v2+uv=0 ⇒uv2+uw2+uvw+v3+vw2+v2w-vu2-v3-uv2-u2w-v2w-uvw=0 ⇒uww-u+vww-v=0⇒uv+vw+wu=0