First slide

Theorems of probability

Question

Three electric lamps are fitted in a room. 3 bulbs are chosen at random from 12 bulbs having 10 good bulbs. The probability that the room is lighted is

Easy

A

_$0$
B

_$1$
C

_{$\frac{1}{^{12} C_{3}}$}
D

_{$1 - \frac{^{10} C_{3}}{^{12} C_{3}}$}

Solution

$P (E) = 1 - \Pr o b a b i l i t y f o r r o o m i s n o t l i g h t e d$
$= 1 - p r o b a b i l i t y o f a l l t h e t h r e e b u l b s a r e d e f e c t i v e$
$= 1 - 0 = 1$

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