Three numbers are chosen at random from the first 20 natural numbers. Then the probability that their product is odd is

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10C3 20C3

1− 10C3 20C3

( 10C1)3 20C3

10C1 20C3

answer is A.

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Detailed Solution

n(S)=20C3 If the product is odd then all the 3 numbers are oddn(E) = 10C3 P(E)= 10C3 20C3 ∴ The probability that their product is odd is 10C3 20C3