First slide
Arithmetic progression
Question

The three numbers a, b, c between 2 and 18 are such  that their sum is 25; the numbers 2, a, b are consecutive terms of an A.P. and the numbers b, c, 18 are  consecutive terms of a G.P. The three numbers are

Moderate
Solution

we have a+b+c=25       (1)

2,a,b are in A.P.,  2a=2+b   (2)

b,c18 are in G.P.,  c2=18b    (3)

From Eq. (1) and (2),

   3b+2c=48; or 3b=482c

 From Eq. (3),

   c2=6(482c)=28812c

or  c2+12c288=0

or  c2+24c12c288=0 (a=b+12)

or  18b=72b=4,

From Eq. (1),

  a=4+12=8

 Hence, the four numbers are 8, –4, 2 and 8.

 

 

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