Questions
Three numbers form a GP. If the 3rd term is decreased by 64, then the three numbers thus obtained will constitute an AP. If the second term
of this AP is decreased by 8, a GP will be formed again, then the numbers will be
detailed solution
Correct option is C
let a, ar, ar2 are in GP and a, ar, ar2 - 64 are in AP, we getar2−2r+1=64 …….(i)Again, a, ar -8, ar2 - 64 are in GP.∴ (ar−8)2=aar2−64⇒ a(16r−64)=64 …..(ii)On solving Eqs.(i) and (ii), we get r =5,a =4Thus, required numbers are 4, 20, 100.Similar Questions
If the roots of the equation,
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