First slide

Theorems of probability

Question

Three six faced dice are tossed together, then the probability that exactly two of the three numbers are equal is

Moderate

A

$\frac{165}{216}$
B

$\frac{177}{216}$
C

$\frac{51}{216}$
D

$\frac{90}{216}$

Solution

$P (E) = \frac{{}^{6}C_{1} \times {}^{5}C_{1} \times \frac{3!}{2!}}{6 \times 6 \times 6} = \frac{90}{216}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App