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Three of the six vertices of a regular hexagon are chosen at random. The probability that the triangle with three vertices is equilateral is
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Correct option is C
Out of 6 vertices, 3 can be chosen 6C3, ways. The triangle will be equilateral if it is ΔACE or ΔBDF (2 ways). Therefore, the required probability is2 6C3=220=110Similar Questions
The odd against an event are 5 to 2 and the odds in favour of another disjoint event are 3 to 5. Then the probability that atleast one of the events will happen is
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