First slide

Theorems of probability

Question

Three squares of a chess board are chosen at random, the probability that two are of one color and one of another is

Moderate

A

$\frac{16}{21}$
B

$\frac{8}{21}$
C

$\frac{32}{12}$
D

$\frac{16}{27}$

Solution

$P (E) = \frac{2 \times {}^{32}C_{2} \times {}^{31}C_{1}}{{}^{64}C_{3}} = \frac{16}{21}$

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