Through the point P(3,4) a pair of perpendicular lines are drawn which meet x-axis at the point A and B. The locus of incentre of triangle PAB is

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x2−y2−6x−8y+25=0

x2+y2−6x−8y+25=0

x2−y2+6x+8y+25=0

x2+y2+6x+8y+25=0

answer is B.

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Detailed Solution

PI = r cosec 450 ⇒PI2=2r2

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