The total number of distinct x ∈ R for which xx21+x32x4x21+8x33x9x21+27x3=10 is _________.

xx21+x32x4x21+8x33x9x21+27x3=10⇒ x3111+x3241+8x3391+27x3=10⇒ x3111241391+x61112483927=10⇒ x310022−136−2+x61002263624=10⇒ 6x6+x3−5=0⇒ 6x3−5x3+1=0⇒ x3=5/6 or x3=−1Two real distinct values of x.