Total number of solutions for the equation x2−3sinx−π6=3 is (where [.] denotes the greatest integer function)
1
2
3
4
Given that x2−3sinx−π6=3
Given equation can be written as x2−3=3sinx−π6
Hence, x2−3=−3,0,3
⇒x=0,x=3 is only solution if x =-3 then 0= sin x-π6 ⇒ 0≤sinx-π6<1 , which is not posible for x=-3
similarly x=±6 does not satisfy the equation