Total number of solutions for the equation is x2−3sinx−π6=3(where [.] denotes the greatest integer function)
1
2
3
4
We have x2−3sinx−π6=3
We can see that sinx-π6≠1 ⇒sinx-π6=-1 or 0 -1≤sinx-π6<1
⇒The given equation becomes x2+3=3 or x2=3 ⇒x=0,3 are the only solutions satisfying the given equation