Combinations
Question
The total number of ways in which a beggar can be given at least one rupee from four 25 p. coins, three 50 p. coins and 2 one rupee coins is
Moderate
Solution
The following four cases are there:
(A) At least one one rupee coin and any number of other coins = 2 × 4 × 5 = 40 ways.
(B) At least two 50 p. coins and any number of 25 p. coins = 2 × 5 = 10 ways.
(C) One 50 p. coin and at least two 25 p. coins = 1 × 3 = 3 ways.
(D) Four 25 p. coins in one way only ∴ total = 54.
Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Recieve an sms with download link
OR
SCAN ME
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
