First slide

Combinations

Question

Total number of ways in which six ‘+’ and four ‘–’ signs can be arranged in a row so that no two ‘–’ signs to be together, is

Easy

A

35
B

70
C

_{$6! \times 4!$}
D

24

Solution

Six ‘+’ signs can be arranged in only 1 ways in 7 gaps,4 ‘-’ signs can be arranged in_{$= \frac{^{7} p_{4}}{4!}$} ways
_{$= 1 \times \frac{^{7} p_{4}}{4!} = 35$}

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