A tower ABCD stands on a level ground with foot A . At a point P on the ground, the portion AB,AC and AD subtends angles α,β and γ respectively. If AB=a,AC=b,AD=c,AP=x and α+β+γ=180° , then (a+b+c)x2=
abc
1abc
a + b - c
a - b - c
From, ΔPAB,tanα=ax
From, ΔPAC,tanβ=bx
From, ΔPAD,tanγ=cx
Given α+β+γ=180
⇒tanα+tanβ+tanγ=tanαtanβtanγ
⇒ax+bx+cx=abcx3
⇒(a+b+c)x2=abc