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Q.

A tower, of x meters high, has a flagstaff at its top. The tower and the flagstaff subtend equal angles at a point distant ‘y’ meters from the foot of the tower. Then the length of the flagstaff in meters is

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a

yx2−y2x2+y2

b

xx2+y2y2−x2

c

xx2+y2x2−y2

d

xx2−y2x2+y2

answer is B.

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Detailed Solution

We  have  tanθ=xy,     tan2θ=h+xy,  ⇒h+x=ytan2θ=y×2tanθ1−tan2θ=y2x/y1−x2/y2=2xy2y2−x2⇒h=2xy2y2−x2−x=2xy2−xy2+x3y2−x2=xy2+x2y2−x2
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