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Q.

The transformed equation x3−52x2−718x+1108=0  by removing fractional coefficients, is

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a

x3−3x2−x+12=0

b

x3−3x2−x+6=0

c

x3−3x2−24x−216=0

d

x3-15x2−14x+2=0

answer is D.

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Detailed Solution

2,2×32,22×33 m=2×3 Transformed Equation  whose roots are multiplied by 6 is  fx6=x63−52x62−718x6+1108=0⇒x3-15x2−14x+2=0
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The transformed equation x3−52x2−718x+1108=0  by removing fractional coefficients, is