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In a trapezium, BC=αAD. We will then find that p=AC+BD  is collinear with AD. If p=μAD  then which of the following is true?

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a
μ=α+2
b
μ+α=1
c
α=μ+1
d
μ=α+1

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detailed solution

Correct option is D

c→−b→=αd→ and p→=AC→+BD→=μAD→ Hence, p→=c→+d→−b→=μd→ (using c→−b→=αd→)or  μ=α+1


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