In a triangle ABC,∠C=π2. If tanA2 and tanB2 are the roots of the equation ax2+bx+c=0(a≠0),then the value of a+bc (where a, b, c are sides of ∆ opposite to angles A, B, C, respectively) is
tanA2+tanB2=−batanA2×tanB2=caA+B=90∘ or A+B2=45∘⇒tanA+B2=1=−ba1−ca
or 1−ca=−baor a+b=cor a+bc=1