In a triangle ABC, if A(2,-1) and 7x-10y+1=0 and 3x-2y+5=0 are equations of an altitude and
an angle bisector respectively drawn from B, then equation of BC is
x+y+1=0
5 x+y+17=0
4 x+9 y+30=0
x-5y-7=0
BD and BE are intersect at B.
∴Co-ordinates of B are(-3,-2)
Also mAB=1/5 ∴tanθ=32-151+310=32-m1+3m2
⇒1=3-2m2+3m or ±1=3-2m2+3m
⇒m=1/5 (rejected) or -5
∴Equation of BC is y+2=-5x+3 ⇒5x+y+17=0
Alternatively: Take image of (2,-1) in the line BD to get a point on BC .