In triangle ABC , tanA+ tan B + tanC= 6 and tanA tanB = 2.then the values of tanA, tanB, tanc are, respectively

ln a triangle, tanA + tanB + tan C = tanA tanB tanC ------------(i)6 = 2tanC or   tanC = 3Also tanA + tanB = 6-3 = 3-------(ii)By Eqs. (i) and (ii), tanA and tanB are roots of  x2 -3x + 2 = 0. Thus,tanA, tan B = 2, 1 or 1,2 and tanC = 3