Q.
In a triangle ABC vertex A is (3,1) and mid point of BC is 52,72 It is also given that orthocentre of ΔABC is H(0,2). If co-ordinates of vertices B and C are X1,Y1 and X2,Y2 respectively. Then Identify correct option(s)
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a
x1−x2+y1−y2=4
b
x1+x2+y1+y2=10
c
If circumcentre is (α,β) then |α−β|=2
d
HO2=15 where O is circum centre of △ABC
answer is A.
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Detailed Solution
In a triangle A BC Equation of line BC is y−72=3x−522y−7=3(2x−5)2y−7=6x−153x−4=y slope of CH slope of AB=−13t−5t−31=−1⇒t=2⇒B=2,2similarly slope of BH slope of AC=−1⇒C=3,5 Hence B and C are (2,2) and (3,5)G=83,83 and HGO 2 : 1 hence O is (4, 3) so correct options are A and B.
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