First slide
Introduction to Determinants
Question

In a triangle, ABC if Δ=1    a    b1    c    a1    b    c=0 then sin2A+sin2B+sin2C is

Moderate
Solution

Evaluating along C1, we get

    Δ=c2ab+b2ac+a2bc=0     (ab)2+(bc)2+(ca)2=0     a=b=cA=B=C=π/3     sin2A+sin2B+sin2C=332

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