First slide

Equation of line in Straight lines

Question

The triangle formed by the lines given by $\sqrt{3} x + y = 0,$ $\sqrt{3} x - y = 0,$ and $y - 2 = 0$

Moderate

A

Right angled
B

Equilateral
C

Isosceles
D

Right angled isosceles

Solution

$The line y - 2 = 0 is a horizontal line.$
$The slope of the line \sqrt{3} x + y = 0 is m = - \sqrt{3} and the slope of the line \sqrt{3} x - y = 0, is m = \sqrt{3}$
$Each acute angle made by these two lines with horizontal line is 60^{\circ}$
It means two angles in a triangle is $60 °$ , therefore, the triangle formed by the given three lines is equilateral triangle.

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