The triangle formed by the points (0,7,10), (- 1,6,6), (- 4,9,6) is

Let A(0,7,10), B(-1,6,6) and C(-4 ,9,6)Then,AB=(−1−0)2+(6−7)2+(6−10)2=1+1+16=18=32BC=(−4+1)2+(9−6)2+(6−6)2=9+9+0=18=32AC=(−4−0)2+(9−7)2+(6−10)2=16+4+16=36=6Clearly  ,AC2=AB2+BC2Hence, triangle is right angled. Also, AB = BC Triangle is right angled isosceles.