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Triangle formed by $x^{2} - 3 y^{2} = 0$ and $x = 4$ is

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isosceles

equilateral

right angled

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Correct option is B

The equations of the sides of the triangle arex2−3y2=0 and x=4 or x+3y=0,x−3y=0 and x=4So, the coordinates of the vertices are O(0, 0), A4, 43 and B4,−43Clearly, OA=OB=AB=83 Hence, ∆ OAB is equilateral.

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Triangle formed by x2−3y2=0 and x=4 is

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Triangle formed by $x^{2} - 3 y^{2} = 0$ and $x = 4$ is