In a triangle the length of the two larger sides are 10 and 9 , respectively. If the angles are in A.P., then the length of the third side can be :
91
33
5
None of these
Since the angles of a triange are in APlet the third side be x⇒(α−δ)+α+(α+δ)=180°⇒α=60°Use cosine law in △ABCcos60°=(10)2+(x)2−922⋅(10)⋅(x)⇒12=19+x220x⇒x2-10x+19=0x=10±100-762=5±6