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Questions  

In a triangle tanA+tanB+tanC=6and tanAtanB=2.

Then the values of tanA,tanBandtanCare

a
1, 2, 3
b
2, 2, 2
c
1, 2, 0
d
None of these

detailed solution

Correct option is A

Since A+B+C=π in triangle ABC, we have⇒tanA+tanB+tanC=tanA tanB tanC⇒                     6=2tanC⇒                                tanC=3                   ∴ tanA+tanB=3, tanA tanB=2⇒                              tanA=1 (or) 2                       and tanB=2 (or) 1

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