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Q.

In a triangle XYZ let a,b,and c be the lengthsof the sides opposite to the  angles X,Y and Zrespectively. If 2a2−b2=c2  and λ=sinX−YsinZ ,then  possible value(s) of n for which cosnπλ=0is (are)In a triangle XYZ  let a,b,and c be the lengthsof the sides opposite to the  angles X,Y and Zrespectively. If 1+cos2X−2cos2Y=2sinXsinY, then possible value(s) of  ab is (are)In  R2 let 3i^+j^,i^+3j^  and βi^+1−βj^ bethe position  vectors of X,Yand Z with respectto the origin O, respectively.If  the distance ofZ from the bisector of acute angle of  OX→withOY→ is 32  then possible value(s) of  β is (are)Suppose that Fα  denotes  the area of theregion bounded by x=0,x=2,y2=4x  and y=αx−1+αx−2+αx,where α∈0,1 ,Then the value(s) of Fα+832,when α=0 andα=1  is (are)

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answer is A-P;R;S,B–P,C–P;Q,D–S;T .

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Detailed Solution

A 2a2−b2=c2⇒2sin2X−sin2Y=sin2Z⇒2sinX+YsinX−Y=sin2Z⇒sinX−YsinZ=12⇒λ=12cosnπλ=0  ⇒cosnπ2=0n=1,3,5B 1+cos2X−2cos2Y=2sinXsinY⇒1+1−2sin2X−21−2sin2Y=2sinXsinY⇒sin2X+sinXsinY−2sin2Y=0sinXsinY=−2  or1but −2  is not possible⇒sinXsinY=1⇒ab=1C Bisectors of OX→&OY→  are x=y  or x+y=0∴β-1-β2=32⇒2β-1=3⇒β=1,2 (D) For α=1                   y=x−1+x−2+x=3−x  ;  x<11+x  ;   1≤x<23x−3;   x≥2                   ∴Area =F1=122+3×1+122+3×1− 022xdx=5−823⇒F1+823=5                       For α=0, y=3.                         ∴Area=F0=2×3−∫0222dx=6−823⇒F0+823=6
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In a triangle XYZ let a,b,and c be the lengthsof the sides opposite to the  angles X,Y and Zrespectively. If 2a2−b2=c2  and λ=sinX−YsinZ ,then  possible value(s) of n for which cosnπλ=0is (are)In a triangle XYZ  let a,b,and c be the lengthsof the sides opposite to the  angles X,Y and Zrespectively. If 1+cos2X−2cos2Y=2sinXsinY, then possible value(s) of  ab is (are)In  R2 let 3i^+j^,i^+3j^  and βi^+1−βj^ bethe position  vectors of X,Yand Z with respectto the origin O, respectively.If  the distance ofZ from the bisector of acute angle of  OX→withOY→ is 32  then possible value(s) of  β is (are)Suppose that Fα  denotes  the area of theregion bounded by x=0,x=2,y2=4x  and y=αx−1+αx−2+αx,where α∈0,1 ,Then the value(s) of Fα+832,when α=0 andα=1  is (are)