The true solution set of inequality log(x+1)⁡x2−4>1=

log(x+1)⁡x2−4>1we have x2−4>0,x+1>0 and x+1≠1∴ x∈(2,∞)-----iCase I:     x+1>1⇒x>0∴    x2−4>x+1∴    x2−x−5>0∴    x∈1+212,∞---iiCase II: (x+1)∈(0,1)⇒ x∈(−1,0)Clearly, this is not possible as  x∈(2,∞)