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Q.

Two adjacent sides of a parallelogram ABCD are 2i^+4j^−5k^ and i^+2j^+3k^ then the value of |AC→×BD→| is

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a

205

b

225

c

245

d

265

answer is B.

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Detailed Solution

∣AC→×BD→∣=2|AB→×AD→|=2i^j^k^24−5123=|2[i^(12+10)−j^(6+5)+k^(4−4)]|=|2[22i^−11j^]|=22|[2i^−j^]|=22×5

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Two adjacent sides of a parallelogram ABCD are 2i^+4j^−5k^ and i^+2j^+3k^ then the value of |AC→×BD→| is