First slide

Theorems of probability

Question

Two cards are drawn from a pack. The probability that one of them is a club and the other is not a club is

Easy

A

$\frac{1}{36}$
B

$\frac{5}{108}$
C

$\frac{26}{51}$
D

$\frac{13}{34}$

Solution

$P (A) = \frac{13_{c_{1}} {.39}_{c_{1}}}{52_{c_{2}}} = \frac{13}{34}$

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