Two cards are drawn successively with replacement from a pack of cards. Taking the random variable X = the number of kings, the variance of X is
2/13
9/13
24/169
1/13
μ=ΣxiP(X=xi)
=0(144169)+1(24169)+2(1169)=26169=213
σ2=Σxi2P(X=xi)−μ2
=0(144169)+1(24169)+4(1169)−4169=24169