Two circles, each of radius 5, have a common tangent at (1, 1) whose equation is 3x+4y-7= 0. Then, their centres, are
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a
(4,-5),(-2, 3)
b
(4,-3),(-2,5)
c
(4,5),(-2,-3)
d
none of these
answer is C.
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Detailed Solution
Clearly, (1, 1) is the mid-point of the line segment joining the centres of the circles and centres lie on the line passing through (1, 1) and perpendicular to 3x+4y−7=0 i.e. 4x−3y−1=0 Clearly, coordinates of points given in option (c) satisfy these two conditions..