Two circles of radius unity each are such that each passes through the centre of the other. If a square is inscribed in the overlapped region, and the area of square is 2−p (p∈Q), then the value of p equals

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answer is C.

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Detailed Solution

12+x2+x2=12⇒x=−1±74⇒x=7−14∴2x=7−12 Area =7−122=4−72=2−74∴P=74=1.75

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