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The two circles $x^{2} + y^{2} - 2 x - 3 = 0$ and $x^{2} + y^{2} - 4 x - 6 y - 8 = 0$ are such that

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they touch each other

they intersect each other

one lies inside the other

each lies outside the other

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detailed solution

Correct option is B

The coordinates of centres C1 and C2 of two circles are (1, 0) and (2, 3) respective. Let r1 and r2 be the radii of two circles. Then, r1=2 and r2=21.Clearly r1−r2

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The two circles x2+y2−2x−3=0 and x2+y2−4x−6y−8=0 are such that

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Ready to Test Your Skills?

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The two circles $x^{2} + y^{2} - 2 x - 3 = 0$ and $x^{2} + y^{2} - 4 x - 6 y - 8 = 0$ are such that