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For the two circles $x^{2} + y^{2} = 16$ and $x^{2} + y^{2} - 2 y = 0$ there is/are

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detailed solution

Correct option is D

The circle x2+y2−2y=0 is completely within x2+y2=16 Hence, there is no common tangent.

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For the two circles x2+y2=16 and x2+y2−2y=0 there is/are

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For the two circles $x^{2} + y^{2} = 16$ and $x^{2} + y^{2} - 2 y = 0$ there is/are