Questions
The two conics and
intersect in 4 concyclic points. Then
a
a1−b1h2=a2−b2h1
b
a1−b1h1=a2−b2h2
c
a1+b1h2=a2+b2h1
d
a1+b1h1=a2+b2h2
detailed solution
Correct option is A
The equation of a conic passing through the intersection of the given conics isa1x2+2h1xy+b1y2−c1+λa2x2+2h2xy+b2y2−c2=0This equation will represent a circle, ifCoeff. of x2 = Coeff. of y2 and Coeff. of xy = 0⇒ a1+λu2=b1+λb2 and 2h1+2λh2=0Eliminating λ, from these two equations, we geta1−b1=h1h2a2−b2⇒a1−b1h2=a2−b2l1Talk to our academic expert!
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