Q.

Two consecutive sides of a parallelogram are 4x + 5y = 0 and 7x + 2y = 0. If the equation to one diagonal is 11x + 7y = 9, then the equation of the other diagonal is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

x−y=0

b

x+y=0

c

x+y=1

d

x-y=1

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Let the equation of sides AB and AD of the parallelogram ABCD be4x+5y=0----(1) and  7x+2y=0---(2)respectively. Solving (l) and (2), we have x = 0, y= 0 A = (0,0) Equation of one diagonal of the parallelogram is11x+7y=9---(3)Clearly, I (0, 0) does not lie on diagonal (3), therefore (3) is the equation of diagonal BD. Solving (1) and (3), we get B≡53,−43 and D≡−23,73 .  Since H is the middle point of BD∴H≡12,12 . Now the equation of diagonal AC which passes through A(0,0) and H12,12 is y−0=0−120−12(x−0) or  y−x=0
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
Two consecutive sides of a parallelogram are 4x + 5y = 0 and 7x + 2y = 0. If the equation to one diagonal is 11x + 7y = 9, then the equation of the other diagonal is