The two consecutive terms in the expansion of (3+2x)74 , which have equal coefficients are
7th and 8th
11th and 12th
30th and 31st
None of these
Given expansion (3+2x)74 lets the consecutive terms are
(∴ Tr+1= nCr xn−r (a)r be the expansion of (x+a)n)
Here Tr+1= 74Cr 374−r (2x)r
And Tr= 74Cr−1 375−r (2x)r−1
The coefficients of these two terms are equal according to given problem
If 74Cr 374−r 2r= 74Cr−1 375−r 2r−1
⇒ 74Cr74Cr−1=375−r 2r−1374−r 2r⇒74Cr74Cr−1=32(∴ nCrnCr−1=n−r+1r)⇒75−rr=32∴r=30
So, T31 and T30 have equal coefficients.